What solution volume is needed to prepare a 0.110 M solution of MgSO4 using 10.3 g of the compound?

The molar mass of MgSO4 is 120.366 g/mol

(A) 9.41x10-3 L (B) 0.778 L (C) 1.11 L (D) 93.6 L

Solution: Molarity = moles of solute/ Liters of solution

We need to use grams given to convert them to moles using the molar mass given.

10.3 g ( 1mol/ 120.366 g) = 0.08557 mol

Now, let's plug in the values for molarity and moles.

0.110 M = 0.08557 mol/ V

V = 0.778L (B)

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